If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8^2+6^2=c^2
We move all terms to the left:
8^2+6^2-(c^2)=0
We add all the numbers together, and all the variables
-1c^2+100=0
a = -1; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-1)·100
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-1}=\frac{-20}{-2} =+10 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-1}=\frac{20}{-2} =-10 $
| 4=-10x+5 | | X^+3x=4 | | 15=20t+4.9t ^2 | | 10=3x/4 | | 4×b=14 | | X=4/3(x-2) | | 2/3x+8=x-8 | | -7r=-6−8r | | t=60t | | 4d=9+5d | | 24x=27-3x | | 7b^2-3b-17=0 | | -13x+10x-31=50 | | 7b2-3b-17=0 | | 2x-12=5x+45 | | x÷6=4.2 | | X/2+x/8=1/8 | | 2y(6+2)=32 | | 4x^2=-8x+221 | | 7(4x-1)-3(5x-13)=4(3x+2)-1 | | 7x+22=28 | | X-14+5x+10=40+x-4x-8 | | 0.2+3x+0.2=1.4+1x+1.4 | | (x+4)^2+(x-4)^2=34 | | V8x+6-7=23 | | 3x^2-5=-4x | | 5x+31=9x+7 | | X+25+3x-10=45+x | | -2=x/3-1 | | 10x-9+3x-5=9x-2+3x | | -5x+30=65 | | 3u+4u=27 |